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15x^2-17x+1=0
a = 15; b = -17; c = +1;
Δ = b2-4ac
Δ = -172-4·15·1
Δ = 229
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{229}}{2*15}=\frac{17-\sqrt{229}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{229}}{2*15}=\frac{17+\sqrt{229}}{30} $
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